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Grex Science Item 63: Power and drag measurements - 1993 _Grand Am_ SE automatic
Entered by drew on Sun Jul 2 19:55:17 UTC 2000:

    As Friday was virtually wind-free, or at least as calm as it gets,
it seemed a good time to do the power requirement measurements on my
latest car. The speed range is not as wide as I would have liked; but
the data should be satisfactory for most purposes.

    The data was fitted to a third degree polynomial with the data
for 80, 70, 60, and 50 MPH as boundary conditions. The resulting
function was within my reaction time for the other data points; so
I judged the results good to two significant figures.

    The calculations file, Lotus 123 format, is in ~drew/grand_am.wk1.

-------
Mass (curb): carpoint.msn.com/Vip/Specifications/Pontiac/Grand%20Am/1993
             2756 lb
Crew &
cargo:        150 lb approx
Fuel:          45 lb approx

Total:       2951 lb


   Speed     Time    Rough     Poly    Accel    Accel     Drag    Power
   (MPH)    (sec)     diff     calc (MPH/sec)  (grav)    (lbf)      (W)
------------------------------------------------------------------------
      80      7.6                80 -0.81462 -0.03713 -109.585   -17500
      75     13.6        6 75.26804 -0.76272 -0.03476 -102.603   -15400
      70     20.8      7.2       70 -0.70066 -0.03194 -94.2551   -13200
      65       28      7.2 65.17786 -0.63885 -0.02912 -85.9406   -11200
      60     36.6      8.6       60 -0.56535 -0.02577 -76.0533    -9100
      55     47.1     10.5 54.53279 -0.47610 -0.02170 -64.0464    -7000
      50     57.6     10.5       50 -0.38737 -0.01765 -52.1108    -5200

Speed vector:           80       70       60       50

Time matrix:             1        1        1        1
                       7.6     20.8     36.6     57.6
                     57.76   432.64  1339.56  3317.76
                   438.976 8998.912 49027.89 191102.9

Inverse:          2.290999 -0.21251 0.006008 -0.00005
                  -2.08755 0.367957 -0.01326 0.000130
                  0.946291 -0.18643 0.008937 -0.00010
                  -0.14973 0.030991 -0.00168 0.000025

Polynom constants:86.44175 -0.88062 0.004350 -8.0E-07

Deriv constants:  -0.88062 0.008701 -2.4E-06

-------------

    As expected, the power requirement, at least for one-minute miles,
is much less than that of an _Impala_'s 25 kW.

    As for overall efficiency, I've measured 30 miles per gallon under
conditions of a mixture of 70 MPH average freeway and variable surface
speeds. Taking 2.3 gallons per hour as the fuel consumption under
standard freeway operations, and 115000 BTU/gallon of fuel, we get
264500 BTU/hour, which is about 77.5 kW. The efficiency, fuel to
propulsion, works out at around 17%. I seem to recall higher efficiencies
with earlier vehicles.

    I'll post results for the station wagon when I manage to get data
for it.



28 responses total.



#1 of 28 by rcurl on Sun Jul 2 21:07:35 2000:

Probably doesn't matter, but doing a least-squares fit of your polynomial
to all the data points, rather than an exact fit to just four, would
distribute the error and provide a more "efficient" parameter estimation. 
Also, if you do an orthogonal polynomial fitting, you can test what
order of polynomial is sufficient.


#2 of 28 by drew on Mon Jul 3 23:22:22 2000:

Thanks. I'll try it soon as I can find some information on least squares and
orthogonal fitting.


#3 of 28 by drew on Tue Jul 4 03:59:48 2000:

Matlab does least-squares, an area wherein Lotus 123 seems to be deficient.
I shall have to see about writing an add-on...

Coefficients are slightly different, but not grossly so. I expect the final
results to be very much the same.


#4 of 28 by rcurl on Tue Jul 4 06:00:35 2000:

In really interesting cases, fitting a third order polynomial to four
points, can give really wild fits. The most important point is to use *all
the data*. An estimator that uses all the data is called an efficient
estimator, and always has the smallest variances of the parameter
estimators. You could illustrate this point by comparing the sum of
squared deviations for the remaining three points when an exact fit is
made to four points, with the sum of squared deviations for a least
squares estimator using all seven points.





#5 of 28 by drew on Sun Jul 9 02:37:43 2000:

I've got data for the other car now; and I've redone the calculations for the
first one. ~drew/cardrag.wk1 does not include code for doing the least-squares
fit, which I did in MatLab using the POLYFIT function, since I don't know how
to get Lotus 123 to do that yet.






 Grand Am:

 Mass (curb): carpoint.msn.com/Vip/Specifications/Pontiac/Grand%20Am/1993
              2756 lb
 Crew &
 cargo:        150 lb approx
 Fuel:          45 lb approx

 Total:       2951 lb

    Speed     Time     Poly    Accel    Accel     Drag    Power    kW*hr
    (MPH)    (sec)     calc (MPH/sec)  (grav)    (lbf)      (W)    /mile
 ------------------------------------------------------------------------
       80      7.6 80.00630 -0.86589 -0.03947    116.5    18624    0.233
       75     13.6 75.07199 -0.78044 -0.03557    105.0    15736    0.210
       70     20.8 69.78537 -0.69032 -0.03146     92.9    12991    0.186
       65       28 65.09877 -0.61376 -0.02797     82.6    10726    0.165
       60     36.6 60.15105 -0.54008 -0.02462     72.7     8712    0.145
       55     47.1 54.83992 -0.47636 -0.02171     64.1     7044    0.128
       50     57.6 50.04656 -0.44146 -0.02012     59.4     5934    0.119

 Polynom constants:87.04021 -0.98765 0.008507 -4.4E-05

 Deriv constants:  -0.98765 0.017014 -1.3E-04

 ========================================================================
 Safari (wagon):

 Mass (curb): carpoint.msn.com/Vip/Overview/Pontiac/Safari/1988.asp
              4182 lb
 Crew &
 cargo:        150 lb approx
 Fuel:          30 lb approx

 Total:       4362 lb

    Speed     Time     Poly    Accel    Accel     Drag    Power    kW*hr
    (MPH)    (sec)     calc (MPH/sec)  (grav)    (lbf)      (W)    /mile
 ------------------------------------------------------------------------
       85      3.7 85.25442 -1.42615 -0.06501    283.6    48174    0.567
       80      8.1 79.40030 -1.23836 -0.05645    246.2    39370    0.492
       74     12.5 74.32544 -1.07195 -0.04886    213.2    31523    0.426
       70     16.8 70.02861 -0.92997 -0.04239    184.9    25870    0.370
       65     22.7 65.03736 -0.76838 -0.03502    152.8    19848    0.305
       60       30 59.99955 -0.62164 -0.02833    123.6    14822    0.247
       55       39 54.92147 -0.52172 -0.02378    103.7    11403    0.207
       50     48.6 50.03282 -0.51370 -0.02341    102.1    10207    0.204

 Polynom constants:90.84928 -1.60061 0.024596 -0.00018

 Deriv constants:  -1.60061 0.049193 -5.5E-04




As expected from rough fuel economy measurements, it takes about twice as much
energy, mile for mile and MPH for MPH, to run the station wagon as it does
the smaller car. A station wagon type hull must somehow be better for drag
than a sedan, since somehow it can do one-minute miles on less than 15 bkW
of power, as compared to 25 kW for the car I first did this experiment with
('81 _Impala_). I'm getting about the same fuel economy, but I've also
typically run the station wagon around 70 MPH instead of 60; and the station
wagon *is* a bit more massive - irrelevant on the highway, but a disadvantage
on surface streets.

Re the odd data point in the station wagon test: I was a bit late in calling
off the 75 MPH mark.


#6 of 28 by rcurl on Sun Jul 9 19:51:54 2000:

Data (and analyses) like these should be inlcuded in car evaluations!


#7 of 28 by gull on Sun Jul 9 20:07:45 2000:

Hmm.  Wonder what the figures would look like for my Econoline.  It has all
the aerodynamic design of a boxcar.  I don't have the tools to do the curve
fitting, though.


#8 of 28 by n8nxf on Mon Jul 10 12:30:52 2000:

It took this mathematical lackey a while to figure out what the heck you were
doing but I think I got it.  I don't know how valuable this sort of data would
be as there are a lot of variables.  Tire type and pressure would be a
significant one that doesn't seem to be addressed here.  Same goes for how
well the wheels are aligned.  As for it being useful for purchasing a car,
the numbers can be easily muddied by options such as roof-racks, side mirrors,
wheel and body trim options, additional suspension components increasing drag
under the car, the mechanical drag added by going from 2WD to 4WD, etc.

Your drag figures for the station wagon seem a little high or the figures for
the sedan are a little low.  I don't see how the drag of the wagon can be over
twice that of the sedan!  Two sedans are more efficient than one station
wagon?  It just doesn't make sense!


#9 of 28 by drew on Mon Jul 10 16:27:34 2000:

It's not a full sized sedan. The '93 _Grand Am_ is a smaller car than in
previous years. In fact, a sedan that I tested over a decade ago was *less*
efficient than the current wagon - 25 kW for one-minute miles, compared with
less than 15 kW for the wagon.

As for the variables, yes, that's a problem. Still, I consider this
information better than none at all.

Re #7: I intend to see about teaching Lotus 123 to do curve fitting (have to
look it up myself first). You might want to collect your data during the next
convenient calm period. You'll need a stretch of highway that is both straight
and level; and a tape recorder, along with a sound card and Windows Sound
Recorder to play it into, will be extremely helpful.


#10 of 28 by rcurl on Mon Jul 10 17:13:54 2000:

There will always be a lot of variables in any comnparison of two cars,
even of identical models. Yet, cars are always being compared! In fact,
the comparisons that are made are seldom as precise as this, in part
because they average driving conditions over some distance. That is
both the strength and weakness of what drew is doing. His measurements
give instantaneous variables, and would have to be also done up and
down hill (for example), etc. Of course, they also don't measure engine
performance - just the power losses. But those are what the engine makes up
for, so this helps separate the contributions of the active (engine)
and passive (vehicle) components. 


#11 of 28 by russ on Wed Jul 12 03:32:12 2000:

Re #7:  It's not that hard to do a least-squares fit with a calculator.
I did my first one with a BASIC program I wrote given an algorithm
on the blackboard, IIRC.  If I was interested, I could probably
derive the algorithm now (I didn't know calculus then).

Re #9:  Instead of a tape recorder, a camcorder might be better.  Just
aim it at the speedo, mention significant events for the soundtrack and
do the timing by frame-counting on your VCR at home.  (This won't work
if your speedometer is a bit sticky, like mine.)

If you can also see the outside in the FOV, the camcorder also allows
you to associate acceleration anomalies with the terrain.

Re #10:  Once power demand is determined, it's not much of a jump to
convert fuel consumption into an overall drivetrain efficiency.  This
can be very illuminating.

One of the complications not mentioned thus far is that crosswinds
will increase vehicle drag in both directions along a road.  This
might, or might not, make a significant change in the numbers derived.
The obvious way to control for it is to test on a calm day.


#12 of 28 by rcurl on Wed Jul 12 05:40:49 2000:

What's still missing is a fuel consumption rate meter.



#13 of 28 by drew on Wed Jul 12 16:48:09 2000:

That would be nice to have. I considered getting one, but they were scarce;
and the one I did see in an auto parts store (calibrated in "miles per gallon
at 35 MPH and 55 MPH), as well as "car computers" in catalogs, were a bit
pricey for me at the time. And I'm still not sure that *any* of them used an
actual fuel flow sensor, rather than a simple vacuum sensor or ignition timing
hookup.


#14 of 28 by gull on Thu Jul 13 03:41:30 2000:

Flat roads are scarce in this part of Minnesota, but if I find one I may try
it.  I just have an idle curiousity as to how the figures would compare to
the Grand Am's.


#15 of 28 by drew on Sat Jul 15 03:18:55 2000:

I have uploaded ~drew/cardrag2.wk1, which now contains least-square code. Once
you have substituted your own data, and stretched or shrunk the column to fit
the number of points, you will need to execute a macro to get Lotus 123 to
do the matrix operations. The macro is activated by typing alt-M, and will
recalc the whole spreadsheet afterward.

A derivation of the least squares method can be found in ~drew/leastsq.doc
(MS Word format). I am confident that it is correct as the numbers it spits
out seem to agree with MATLAB's results.


#16 of 28 by n8nxf on Tue Jul 18 02:35:24 2000:

You could compensate for flatness and wind by running the test in both
directions.  (Is the most efficient shape that of a falling rain drop?)


#17 of 28 by rcurl on Tue Jul 18 06:39:52 2000:

A falling rain drop looks like a pancake, somewhat thickened around the
periphery. It looks *nothing* like the metaphorical "teardrop".  In fact,
it takes the shape that has nearly the maximum possible drag! 



#18 of 28 by n8nxf on Tue Jul 18 11:58:28 2000:

Interesting! I didn't know that.  So what shape has the least amount of
drag?


#19 of 28 by rcurl on Tue Jul 18 16:07:08 2000:

Something like the *proverbial* raindrop!

In regard to the shape of a real raindrop, consider that the maximum
pressure due to its fall velocity occurs at its 'nose'. Since the drop
is deformable, the nose gets pushed in, and the result is the deformed
pancake. This shape and air turbulence leads to the shape continually
and rapidly deforming. The drops you see fall so fast you can't see
all the bizarre shapes they take. Surface tension is fighting these
shape changes, so very small drops approach spheres and the shapes get
more irregular as the size increases, until the irregular motions
of the drops lead them to break up. 


#20 of 28 by gull on Tue Jul 18 18:01:41 2000:

Most people assume the most aerodynamic shape looks like a rocket, with a
very sharp, tapered nose.  The Concorde is another example of this shape. 
However, rockets and the Concorde are both made to fly at *supersonic*
velocities.  The most efficient shape at subsonic speeds has a rounded nose
and a tapered tail -- as rcurl says, much like a teardrop.  Look at a 747;
blunt, rounded nose at the front, long, tapered tailcone at the rear.  The
GM EV-1 is also a pretty good example; it has the lowest drag coefficent of
any production car, IIRC.  Somewhere around 0.19.  (It has only 19% the drag
of a flat plate the same size as its frontal area.)  For comparison, most
pickup trucks have drag coefficients around 0.75.


#21 of 28 by russ on Wed Jul 19 00:30:56 2000:

Re #10:  Considering that a falling raindrop is somewhere between
spherical (for the really small ones) to hamburger-shaped (for
the larger ones)... I'd guess not.


#22 of 28 by drew on Wed Jul 19 17:11:04 2000:

On drag coefficients, it should be noted that it is necessary to specify just
what dimensions you are counting as the "area" for the purpose. #20 specified
the frontal area. However, airfoils generally have drag - and lift -
coefficients listed based on the area of the top of the wing, ie, the large
surface.

The drag coefficient - or rather, that part of it that is not induced by lift,
is largely dependent on the Renolds number, another dimensionless quantity
based partly on the size of the object. Like with drag coefficients, the
Renolds number must be given in context of which dimensions of the object are
used as its size.


#23 of 28 by gull on Wed Jul 19 18:20:22 2000:

Very true.  I was under the impression (possibly wrong) that for automobiles
the quoted drag coefficient is usually the frontal area.  You need to know
both to get any idea of how "aerodynamic" the object really is.  For example,
a 1960's VW bus has a better drag coefficent than a Beetle of the same era
-- the bus has a rounded nose and flat sides, and the Beetle has a flat
windshield and wide fenders that stick out into the airstream.  The Beetle's
frontal area is so much smaller, though, that the total drag ends up being a
lot less.  On flat ground the Beetle will do 80 with roughly the same amount
of power it takes to get the bus to do 60.


#24 of 28 by rcurl on Wed Jul 19 23:49:56 2000:

That's Reynolds number.

The lift is at right angles to the drag. By definition, drag and lift
are separate, orthogonal, forces. One can't say lift contributes to
drag, therefore. Of course, the whole profile contributes to both
drag and lift. The "projected frontal area" convention for a drag
coefficient is just that - a convention to define the drag coeff.


#25 of 28 by drew on Sun Nov 17 03:58:18 2002:

 Escort Wagon

 Mass (curb): autos.msn.com/Vip/Specifications.aspx?modelid=1064&src=vip
              2513 lb
 Crew &
 cargo:        160 lb approx
 Fuel:          60 lb approx

 Total:       2733 lb

    Speed     Time     Poly    Accel    Accel     Drag    Power    kW*hr
    (MPH)    (sec)     calc (MPH/sec)  (grav)    (lbf)      (W)    /mile
 ------------------------------------------------------------------------
       80     7.87 79.76637 -1.15239 -0.05253    143.6    22954    0.287
       75     11.7 75.43812 -1.10717 -0.05047    137.9    20675    0.276
       70     16.8 69.95688 -1.04123 -0.04746    129.7    18148    0.259
       65       22 64.73187 -0.96724 -0.04409    120.5    15654    0.241
       60     27.2 59.90930 -0.88644 -0.04040    110.4    13243    0.221
       55     32.7 55.28575 -0.79357 -0.03617     98.9    10867    0.198
       50     40.1 49.91168 -0.65658 -0.02993     81.8     8174    0.163

 Polynom constants:         89.16584 -1.23369 0.004669 0.000042
 Deriv constants:           -1.23369 0.009338  1.3E-04

    This car turns out to be, on rough average, about 40% harder to push
than the Grand Am was, which explains the lower fuel economy. In fact,
the Escort's engine is actually more efficient at producing power, since
it only consumes 20% more fuel over a given distance (25 MPH versus 30
MPG) instead of the full 40% extra.

    Curiously, the Escort wagon wins big over the Safari wagon at higher
speeds, but loses most of this advantage around the 55 MPH mark:

     Speed      Escort        Safari      Escort's         
     (MPH)   (kW*hr/mile)  (kW*hr/mile)   Savings
    -----------------------------------------------
       80       .289          .492          42%
       75       .278          .426          35%
       70       .261          .370          30%
       65       .243          .305          21%
       60       .222          .247          11%
       55       .199          .207           4.3% (!)
       50       .165          .204          20%

At around 55 MPH, there is less than a 5 percent difference between the
hull drag of an Escort and a Safari wagon. At 50 MPH (and presumably
below), the advantage of lower drag reappears.


#26 of 28 by gull on Mon Nov 18 16:01:36 2002:

Maybe some day I'll try to get figures for my '94 Honda Civic hatchback
and my '82 Volkswagen Vanagon Westfalia.  The Vanagon drag figures ought
to be amusing.


#27 of 28 by drew on Fri May 25 03:16:00 2007:

_Windstar_ class minivan:

    For this one I had on hand a video camera.

    Test conducted 2007:05:20; temperature 63 degrees F, barometric
pressure 30 inches of mercury, for an air density of 1.219 kg/m^3.
Intellicast reported wind from the north at 11 MPH, which I judged
small enough compared to the test speed range, or at least as light
as it usually gets.

    Beforehand I had determined that the speedometer and odometer both
read about 15% short. The other vehicles that I tested had accurate gauges.

    The highway in the test location runs along course 71 degrees (ENE) and
251 degrees (WSW). For this test I managed to get data for each direction.

Mass
Curb mass  3711.4  lb
Fuel         75
Self        150
Misc         50

Total:     3936.4  lb

Polynomial approximation: V = sum( Ak t^k );  a = sum( k Ak t^k )

East-Northeast run:
  Speed      Speed    Time   Poly    Accel    Accel   Drag   Power   kW*hr
(MPH, raw) (correct) (sec)   calc  (MPH/sec) (grav)  (lbf)    (W)    /mile
-----------------------------------------------------------------------------
   77.5      89.13    16.0  88.82   -1.577  -0.0719  282.99  49985  0.56274
   75        86.25    18.0  85.72   -1.521  -0.0694  273.01  46539  0.54289
   70        80.50    21.4  80.71   -1.427  -0.0650  256.04  41094  0.50914
   65        74.75    25.4  75.23   -1.316  -0.0600  236.06  35313  0.46942
   60        69.00    29.6  69.95   -1.199  -0.0546  215.09  29917  0.42771
   55        63.25    35.5  63.36   -1.034  -0.0472  185.62  23387  0.36910
   50        57.50    42.7  56.63   -0.834  -0.0380  149.64  16852  0.29756
   45        51.75    50.3  51.10   -0.622  -0.0284  111.65  11345  0.22202
   40        46.00    59.4  46.59   -0.369  -0.0168   66.14   6128  0.13153

West-Southwest run:
  Speed      Speed    Time   Poly    Accel    Accel   Drag   Power   kW*hr
(MPH, raw) (correct) (sec)   calc  (MPH/sec) (grav)  (lbf)    (W)    /mile
-----------------------------------------------------------------------------
   76.5      87.98    14.5  87.78   -1.381  -0.0630  247.80  43255  0.49276
   75        86.25    16.0  85.74   -1.348  -0.0614  241.89  41238  0.48100
   70        80.50    19.8  80.77   -1.264  -0.0576  226.90  36443  0.45119
   65        74.75    24.6  74.96   -1.159  -0.0528  207.96  30997  0.41354
   60        69.00    29.2  69.86   -1.058  -0.0482  189.81  26367  0.37744
   55        63.25    35.8  63.35   -0.913  -0.0416  163.76  20631  0.32564
   50        57.50    43.5  56.98   -0.743  -0.0339  133.36  15110  0.26518
   45        51.75    52.8  51.02   -0.538  -0.0245   96.62   9803  0.19213
   40        46.00    63.5  46.52   -0.303  -0.0138   54.34   5026  0.10805

  I don't have figures for actual fuel economy yet - getting them requires
filling the tank - *twice*. The behavior of the fuel gauge suggests
a rate of about 19 MPG on surface streets and *maybe* 25 MPG on
nonstop highways. I plan to get better instrumentation at some point.

    25 MPG at 75 MPH is 3 gallons per hour, or about 100 kW. 20 MPG would
be 3.75 gallons per hour, or about 130 kW. This implies a total drivetrain
efficiency ranging from 23% to 31%. While still not exactly stellar (the
ideal for a 9:1 compression ratio air standard otto cycle is 58.5%), it's
significantly better than those of the _Escort_ and _Grand Am_.

    These test results and other analysis will henceforth appear at
http://drew4096.livejournal.com.


#28 of 28 by gull on Wed Aug 22 17:00:44 2007:

You know, looking back at this, I'm rather shocked that the Escort Wagon
could only manage 25 mpg.  It's not that big a car.

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