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Heh! Just read about Goedel's theorem--here's a goodie! Goedel, after much work, proved that our system of logical reasoning is inconsistant using--here's the catch--our system of logical reasoning. So if this system of logic is wrong, then Goedel's proof is wrong, so our system is right after all. That's kinda like the one where the professor tells the class about a system of time travel that he developed, so they plot to go back in time to kill the professor. This means that the professor couldn't have invented time travel, being dead, so the students couldn't have killed him, so he would have lived after all. The point of that paradox is to prove that time travel is impossibel, so does that mean that the first one proves that logic is impossible?
24 responses total.
A quick scan of how the world runs itself will tell you that logic is a
manufactured concept!
AAAAAAAAAAaaaaaaaa.......!!!!!!
I'm confused.
Dammit, pseudos aren't allowed to be smarter than their creators, orin!
yes they are!
Dammit orin, I'm a model, not a vulcan!
Would'nt time travel take you back to a point intime where as all outcomes from this moment in time are different from the reality you left in the future. Time is a tree with many branches. As you climb up you have many choices which branch to take. Time traveling in the past would give you the opportunity to take different paths as you head to the top branches where you die. And stop thinking time is linear!
Indeed, time is not linear, so much as it is a vibrational frequency.
How true
Orinoco, please tell us more about Goedel's theorem. I'm really interested. Could you state his proof?
yes, please?
ooorin...
I just mailed him the entire item to try to get him to come back
here and enlighten us.
Hope it works.
8*)
Alright, here's what Goedel did. <orinoco thumbs through a generic dusty tome> To do this, i must first define two terms. First, the term "proof pair". the two statements A and B are a proof-pair if you can proove B by starting with A as an axiom. Suppose that statement A is "x=1" and statement B is "x+1=2" Then, the two statements would form a proof-pair. You can prove B, using algebra, from statement A. Is everybody still with me? Any questions?
go on..
..ditto..
Ok, now for the next step. Suppose that any logical statement could be transformed into a number, three digits for each symbol. Thus, if x was 111 in this code, 1 was 222, and = was 333, the statement x=1 (our friend statement A) would become 111333222. We can then say that two *numbers* form a proof-pair if the two *statements* that they translate into form a proof-pair. Now, suppose that there is another function, call it arithmoquine, that acts on two numbers to produce a one-number result. (I am not exactly clear on *how* the arithmoquine function works, more on that later) Then, make a statement (call it G) in the logical symbols of your choice that says the following: Rthere arenUt two numbers, x and y, such that they form a proof-pair, *and* x is the arithmoquine of a number called uS now, as it turns out, Goedel figured out what number u is, and (this is the sneaky part) *when you arithmoquine u, you get the statement G!* So what Goedel is saying in statement G is that Rthere arenUt two numbers, x and y, such that they form a proof-pair, and x is statement GS cleaning it up a little more you get Rthere is no number, y, such that G and y form a proof-pairS or, better yet, Rthere is no statement that you can prove *this statement* fromS Eat your heart out, Spock
those R's and S's should be "'s
I'm still confused.
what part don't you get....i realize that it can be confusing, but i can't help unless i know what you need help on....
The MAJORITY of it.
Pretty much, he just made a statement that says "YOU CAN'T PROVE ME!" if it's a true statement, then you can't prove it, and if there's a true statement you can't prove then logic must be flawed... if it's false, you CAN prove it, and if you can prove something false then logic must be flawed....
Logic IS flawed. That should be a given.
you can't even avoid the problem by inserting the idea of unprovable statements...."you can prove that this is false" should work....
P -> -P "You can prove this is false" in predicate notation -P v -P Equiv -P Equiv "You can prove this is false" is therefore a false statement.
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