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| Author |
Message |
| 13 new of 137 responses total. |
dpc
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response 125 of 137:
| 
Feb 12 14:30 UTC 1998 |
Was anything said at last night's staff meeting about finishing the
security work on the 670? Or about finding an alternative if Steve
Andre can't do it in a reasonable time?
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jep
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response 126 of 137:
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Feb 12 14:42 UTC 1998 |
#119 was a pointed question. Nothing should be discussed in a public
meeting which is not public knowledge. Anything discussed at the last
Board meeting should be (and probably is) available to anyone who's
interested.
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rcurl
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response 127 of 137:
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Feb 12 19:23 UTC 1998 |
This stimulated me to measure my system. It draws overall about 1.4 amps
(ca. 160 watts). The CPU takes most of that. I can't even measure the
printers when they aren't printing.
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mta
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response 128 of 137:
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Feb 13 02:49 UTC 1998 |
> Nothing should be discussed in a public meeting which is not public >
knowledge.
Good point.
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gibson
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response 129 of 137:
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Feb 13 03:02 UTC 1998 |
Mine is all old equipment. The Measurments are from 12 v thru a very
efficient inverter. I under stand if you shop the right components you can
get the whole system under 4 amps at 117v. 12v would probably be 5-6 amps
which still beats the old equipment by a lot. Any one wanting low draw systems
should call Air Castle Enterprises ( or computers, iforget which) in
Southfield.
If anybody has a CPU to upgrade my 486sx please mail me info.
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n8nxf
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response 130 of 137:
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Feb 13 12:21 UTC 1998 |
(4 A @ 117 v ~ 468 watts; 6 A @ 12 v ~ 72 watts, therefore inverter
efficiency = 468 W / 72 W ~ 650%... Dang good! ;-)
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gibson
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response 131 of 137:
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Feb 14 03:41 UTC 1998 |
Did i mention math is not my strong point? The 12v is measured, i don't
have an ac ammeter yet so my 2 am guestimate @may be a little off.@
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n8nxf
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response 132 of 137:
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Feb 16 13:26 UTC 1998 |
(The power supply in my HP 486DX/66 is rated for 70 watts. The monitor
is about 200 watts.)
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rcurl
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response 133 of 137:
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Feb 16 20:38 UTC 1998 |
Is that measured, or only "rated"?
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janc
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response 134 of 137:
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Feb 20 16:09 UTC 1998 |
Has anyone converted the 10amps number reported above into dollars/month?
I'm not sure if I'm doing this right:
(10 amps) (110 volts) = (1100 watts) = 1.1 kilowatts
(1.1 kilowatts) (24 hours/day) ( 30 days/month ) = 792 kilowatt-hours/month
Looking at some of my electric bills, it looks like Det Ed charges about
10 cents per kilowatt hour (or a bit less - about 0.095 dollars per kilowatt
hour).
(792 kilowatt-hours/month) (0.095 dollars/kilowatt-hour) = $75.24 / month
Maybe I should be using 120 volts instead of 110. Then it would be $82 per
month.
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gibson
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response 135 of 137:
|
Feb 20 23:22 UTC 1998 |
The figures look right. It's a power hog.
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tsty
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response 136 of 137:
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Feb 21 08:47 UTC 1998 |
power factor frm a cpu is most likely not too darn large since
sewitching power supplkies are used and they tend not to have
monster transformers with lots of inductance lag (therefore
a bad power factor).
if the voltage is actually running around 118-120, using 110 for
figuring watts is probably about right - at least close enough
i would guess.
i know weh ahve some honking disks on that machine... even so
that 10 amps does seem a bit much.. was that rms amps or peak amps?
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dpc
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response 137 of 137:
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Feb 21 18:07 UTC 1998 |
I'm freezing this item because it's drifted. Maybe someone should
start a new "power" item.
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