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ric
Math Problem Mark Unseen   Dec 12 14:13 UTC 2000

A farmer has a circular pen for his donkey.  The donkey's rope is tied to one
of the posts on the perimeter of the pen.  The rope allows the donkey to reach
exactly 50% of the area of the pen.  Assume that the donkey's reach extends
only as far as the rope does.

How long, as a percentage of the diameter of the circular pen, is the rope?
20 responses total.
flem
response 1 of 20: Mark Unseen   Dec 12 15:43 UTC 2000

I set it up, but I'm too lazy to do the integral right now.  :)
carson
response 2 of 20: Mark Unseen   Dec 12 17:08 UTC 2000

View hidden response.

wjw
response 3 of 20: Mark Unseen   Dec 12 20:23 UTC 2000

The rope is *about* 0.58 times the diameter.   Looking at this number
and trying to recognize something that looks familiar, I'm going to 
guess that the rope is 4/7ths of the diameter (which would be 0.571428
times the diameter).  Just a guess.
flem
response 4 of 20: Mark Unseen   Dec 13 16:57 UTC 2000

I've got a meeting coming up in a few minutes, so maybe I'll set it up and
solve it there.  I'll need something to do.  ;)
nspeed
response 5 of 20: Mark Unseen   Dec 15 22:30 UTC 2000

I get the following monstrous equation:

4arccos(P)*P^2 + 2(pi - arccos(P)) = SQRT[(4P^2 - 1)(1 - cos[2(pi -
arccos(P)))])^2]

, where P = rope length / pen diameter and all the trigonometry is to be
carried out in radians.  I suppose this could be solved graphically, or by
other means. 
Problems like this are fun until you actually try to get a number..
flem
response 6 of 20: Mark Unseen   Dec 15 23:30 UTC 2000

Yeah.  I tried the integral during that meeting, which was fun, but I ended
up with something that I needed tables to reduce, and didn't have any tables
with me.  Lack of forethought, I suppose.  Then I tried something clever, and
came up with something that was harder to set up, but if I'd kept to it, might
have led to a readable answer.  But I didn't.  
carson
response 7 of 20: Mark Unseen   Dec 15 23:40 UTC 2000

(it sounds as if you guys are overanalyzing the problem.  try starting
with area being equal to the value of pi, multiplied by the square of
the radius.  one area's half the size of the other.)
nspeed
response 8 of 20: Mark Unseen   Dec 16 02:06 UTC 2000

but the area the donkey can reach is not a circle, right?
remmers
response 9 of 20: Mark Unseen   Dec 16 02:23 UTC 2000

Right.  The donkey is tied to the perimeter of the pen, so the
area that the donkey can reach will be the intersection of two
overlapping circles.
carson
response 10 of 20: Mark Unseen   Dec 16 12:10 UTC 2000

(right, but the area the donkey *can't* reach is a circle, and just
happens to have the same area as what the donkey *can* reach.)

remmers
response 11 of 20: Mark Unseen   Dec 16 12:38 UTC 2000

No, the area the donkey can't reach is a kind of crescent moon shape.
ric
response 12 of 20: Mark Unseen   Dec 16 15:22 UTC 2000

re 10 - that's definately not true.. 
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